The table shows the number of pets kept by 30 students in a class. We need to find the probability that a randomly picked student kept more than one pet.

1. Problem Description

The table shows the number of pets kept by 30 students in a class. We need to find the probability that a randomly picked student kept more than one pet.

2. Solution Steps

From the table, we have the following information:

- 8 students have 0 pets.

- 4 students have 1 pet.

- 5 students have 2 pets.

The total number of students is

3

0. We are given that in the problem.

The number of students who have more than one pet is the number of students who have 2 pets, which is

5. The probability of a student having more than one pet is the number of students with more than one pet divided by the total number of students.

$P(\text{more than one pet}) = \frac{\text{Number of students with more than one pet}}{\text{Total number of students}}$

$P(\text{more than one pet}) = \frac{5}{30}$

We can simplify this fraction by dividing both the numerator and the denominator by

5. $P(\text{more than one pet}) = \frac{5 \div 5}{30 \div 5} = \frac{1}{6}$

3. Final Answer

The probability that a student kept more than one pet is $\frac{1}{6}$.