We are given that triangles $HKL$ and $HIJ$ are similar. We need to find which of the given ratios is equal to $\frac{LH}{JH}$.

GeometrySimilar TrianglesRatiosProportions
2025/4/29

1. Problem Description

We are given that triangles HKLHKL and HIJHIJ are similar. We need to find which of the given ratios is equal to LHJH\frac{LH}{JH}.

2. Solution Steps

Since HKLHIJ\triangle HKL \sim \triangle HIJ, the corresponding sides are proportional.
This means:
HKHI=HLHJ=KLIJ\frac{HK}{HI} = \frac{HL}{HJ} = \frac{KL}{IJ}
We are looking for a ratio that is equal to LHJH\frac{LH}{JH}. Since LH=HLLH = HL and JH=HJJH = HJ, we can rewrite the required ratio as HLHJ\frac{HL}{HJ}.
From the similarity relation, we have HLHJ=HKHI\frac{HL}{HJ} = \frac{HK}{HI}.
Also, HLHJ=KLIJ\frac{HL}{HJ} = \frac{KL}{IJ}.
Let's look at the given options:
A. KLJI=KLIJ\frac{KL}{JI} = \frac{KL}{IJ}. This is the inverse of IJKL\frac{IJ}{KL}. So KLJI=HLHJ\frac{KL}{JI} = \frac{HL}{HJ}. Therefore LHJH=KLJI\frac{LH}{JH} = \frac{KL}{JI}. The options are not correct because JIJI is the same as IJIJ, therefore A can be rewritten as KLIJ\frac{KL}{IJ}. This is the correct match, hence LHJH=KLIJ\frac{LH}{JH} = \frac{KL}{IJ}.
B. HKJK\frac{HK}{JK}. This is not in the same form as HKHI\frac{HK}{HI}.
C. JIKL\frac{JI}{KL}. Since JIJI is the same as IJIJ, this becomes IJKL\frac{IJ}{KL}, which is the inverse of KLIJ\frac{KL}{IJ}. So IJKL=HJHL\frac{IJ}{KL} = \frac{HJ}{HL}. Since HJHL\frac{HJ}{HL} is equal to 1HLHJ\frac{1}{\frac{HL}{HJ}}, it is the inverse of what we want. Therefore C is not the answer.
Therefore, the answer should be A. The ratio LHJH\frac{LH}{JH} is equal to KLJI\frac{KL}{JI} which is the same as KLIJ\frac{KL}{IJ}.

3. Final Answer

A. KLJI\frac{KL}{JI}

Related problems in "Geometry"

The problem asks us to find the volume of a cylindrical litter bin in m³ to 2 decimal places (part a...

VolumeCylinderUnits ConversionProblem Solving
2025/6/10

We are given a triangle $ABC$ with $AB = 6$, $AC = 3$, and $\angle BAC = 120^\circ$. $AD$ is an angl...

TriangleAngle BisectorTrigonometryArea CalculationInradius
2025/6/10

The problem asks to find the values for I, JK, L, M, N, O, PQ, R, S, T, U, V, and W, based on the gi...

Triangle AreaInradiusGeometric Proofs
2025/6/10

In triangle $ABC$, $AB = 6$, $AC = 3$, and $\angle BAC = 120^{\circ}$. $D$ is the intersection of th...

TriangleLaw of CosinesAngle Bisector TheoremExternal Angle Bisector TheoremLength of SidesRatio
2025/6/10

A hunter on top of a tree sees an antelope at an angle of depression of $30^{\circ}$. The height of ...

TrigonometryRight TrianglesAngle of DepressionPythagorean Theorem
2025/6/10

A straight line passes through the points $(3, -2)$ and $(4, 5)$ and intersects the y-axis at $-23$....

Linear EquationsSlopeY-interceptCoordinate Geometry
2025/6/10

The problem states that the size of each interior angle of a regular polygon is $135^\circ$. We need...

PolygonsRegular PolygonsInterior AnglesExterior AnglesRotational Symmetry
2025/6/9

Y is 60 km away from X on a bearing of $135^{\circ}$. Z is 80 km away from X on a bearing of $225^{\...

TrigonometryBearingsCosine RuleRight Triangles
2025/6/8

The cross-section of a railway tunnel is shown. The length of the base $AB$ is 100 m, and the radius...

PerimeterArc LengthCircleRadius
2025/6/8

We are given a quadrilateral ABCD with the following angle measures: $\angle ABC = 14^{\circ}$, $\an...

QuadrilateralAnglesAngle SumReflex Angle
2025/6/8