The problem asks us to simplify the expression $\frac{2}{2+x} + \frac{2}{2-x}$.

1. Problem Description

The problem asks us to simplify the expression $\frac{2}{2+x} + \frac{2}{2-x}$.

2. Solution Steps

To add the two fractions, we need to find a common denominator. The common denominator is $(2+x)(2-x)$. We can rewrite the expression as follows:

$\frac{2}{2+x} + \frac{2}{2-x} = \frac{2(2-x)}{(2+x)(2-x)} + \frac{2(2+x)}{(2+x)(2-x)}$

Now that the fractions have the same denominator, we can add the numerators:

$\frac{2(2-x) + 2(2+x)}{(2+x)(2-x)} = \frac{4-2x + 4+2x}{(2+x)(2-x)}$

Simplify the numerator:

$\frac{8}{(2+x)(2-x)}$

Simplify the denominator using the difference of squares formula:

$(a+b)(a-b) = a^2 - b^2$

$(2+x)(2-x) = 2^2 - x^2 = 4-x^2$

So the expression becomes:

$\frac{8}{4-x^2}$

3. Final Answer

The simplified expression is $\frac{8}{4-x^2}$. The answer is B.