The problem states that a rectangle has a length of $x$ cm and a width of $(x - 1)$ cm. The perimeter of the rectangle is 16 cm. We need to find the value of $x$.

AlgebraPerimeterRectanglesLinear EquationsSolving Equations
2025/4/29

1. Problem Description

The problem states that a rectangle has a length of xx cm and a width of (x1)(x - 1) cm. The perimeter of the rectangle is 16 cm. We need to find the value of xx.

2. Solution Steps

The formula for the perimeter of a rectangle is:
P=2l+2wP = 2l + 2w
where PP is the perimeter, ll is the length, and ww is the width. We are given that P=16P = 16, l=xl = x, and w=x1w = x - 1. Substituting these values into the perimeter formula, we get:
16=2(x)+2(x1)16 = 2(x) + 2(x - 1)
Now we solve for xx:
16=2x+2x216 = 2x + 2x - 2
16=4x216 = 4x - 2
16+2=4x16 + 2 = 4x
18=4x18 = 4x
x=184x = \frac{18}{4}
x=92x = \frac{9}{2}
x=412x = 4\frac{1}{2}

3. Final Answer

The value of xx is 4124\frac{1}{2} cm.
The correct answer is C. 4124\frac{1}{2} cm.

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