The problem states that the mean of the numbers 2, 5, 2x, and 7 is less than or equal to 5. We need to find the range of values of x that satisfy this condition.

AlgebraInequalitiesMeanSolving Inequalities
2025/4/29

1. Problem Description

The problem states that the mean of the numbers 2, 5, 2x, and 7 is less than or equal to

5. We need to find the range of values of x that satisfy this condition.

2. Solution Steps

The mean of a set of numbers is the sum of the numbers divided by the number of elements in the set. In this case, the mean of 2, 5, 2x, and 7 is given by:
2+5+2x+74\frac{2 + 5 + 2x + 7}{4}
The problem states that this mean is less than or equal to

5. So we can write the inequality:

2+5+2x+745\frac{2 + 5 + 2x + 7}{4} \le 5
First, simplify the numerator:
14+2x45\frac{14 + 2x}{4} \le 5
Multiply both sides of the inequality by 4:
14+2x2014 + 2x \le 20
Subtract 14 from both sides:
2x20142x \le 20 - 14
2x62x \le 6
Divide both sides by 2:
x62x \le \frac{6}{2}
x3x \le 3

3. Final Answer

The range of values for x is x3x \le 3.
The answer is A.

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