We are given three sub-problems. a) Express $(\frac{13}{15} - \frac{7}{10})$ as a percentage. b) Factorize the expression $ay - y - a + 1$. c) In a community of 9400 people, the number of women exceeds the number of men by 1500. Find the ratio of men to women.

AlgebraFractionsPercentageFactorizationRatioLinear Equations
2025/4/29

1. Problem Description

We are given three sub-problems.
a) Express (1315710)(\frac{13}{15} - \frac{7}{10}) as a percentage.
b) Factorize the expression ayya+1ay - y - a + 1.
c) In a community of 9400 people, the number of women exceeds the number of men by
1
5
0

0. Find the ratio of men to women.

2. Solution Steps

a) To express (1315710)(\frac{13}{15} - \frac{7}{10}) as a percentage, first find the difference between the fractions. The least common multiple (LCM) of 15 and 10 is
3

0. So, $\frac{13}{15} = \frac{13 \times 2}{15 \times 2} = \frac{26}{30}$ and $\frac{7}{10} = \frac{7 \times 3}{10 \times 3} = \frac{21}{30}$.

Therefore, 1315710=26302130=262130=530=16\frac{13}{15} - \frac{7}{10} = \frac{26}{30} - \frac{21}{30} = \frac{26-21}{30} = \frac{5}{30} = \frac{1}{6}.
To express 16\frac{1}{6} as a percentage, multiply by 100: 16×100=1006=503=1623\frac{1}{6} \times 100 = \frac{100}{6} = \frac{50}{3} = 16\frac{2}{3}.
So, the percentage is 1623%16\frac{2}{3}\%.
b) To factorize the expression ayya+1ay - y - a + 1, we can use factoring by grouping.
ayya+1=y(a1)(a1)=(a1)(y1)ay - y - a + 1 = y(a-1) - (a-1) = (a-1)(y-1).
c) Let mm be the number of men and ww be the number of women in the community.
We are given that m+w=9400m + w = 9400 and w=m+1500w = m + 1500.
Substitute the second equation into the first equation:
m+(m+1500)=9400m + (m + 1500) = 9400.
2m+1500=94002m + 1500 = 9400.
2m=94001500=79002m = 9400 - 1500 = 7900.
m=79002=3950m = \frac{7900}{2} = 3950.
Now find the number of women: w=m+1500=3950+1500=5450w = m + 1500 = 3950 + 1500 = 5450.
The ratio of men to women is m:w=3950:5450m:w = 3950:5450.
Simplify the ratio by dividing both sides by their greatest common divisor (GCD).
Both numbers are divisible by
5

0. $\frac{3950}{50} = 79$ and $\frac{5450}{50} = 109$.

Since 79 is a prime number, and 109 is a prime number, the GCD is
5

0. So, the ratio is $79:109$.

3. Final Answer

a) 1623%16\frac{2}{3}\%
b) (a1)(y1)(a-1)(y-1)
c) 79:10979:109

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