The problem requires us to complete a table of values for the linear equation $2x + 5y = 10$ and then draw the graph of the equation. The table has two values we need to find: the value of $y$ when $x = 0$, and the value of $x$ when $y = 0$.

AlgebraLinear EquationsGraphingCoordinate Geometry
2025/4/30

1. Problem Description

The problem requires us to complete a table of values for the linear equation 2x+5y=102x + 5y = 10 and then draw the graph of the equation. The table has two values we need to find: the value of yy when x=0x = 0, and the value of xx when y=0y = 0.

2. Solution Steps

First, we find the value of yy when x=0x = 0. We substitute x=0x = 0 into the equation:
2(0)+5y=102(0) + 5y = 10
0+5y=100 + 5y = 10
5y=105y = 10
y=105y = \frac{10}{5}
y=2y = 2
Next, we find the value of xx when y=0y = 0. We substitute y=0y = 0 into the equation:
2x+5(0)=102x + 5(0) = 10
2x+0=102x + 0 = 10
2x=102x = 10
x=102x = \frac{10}{2}
x=5x = 5
Now, we have two points: (0,2)(0, 2) and (5,0)(5, 0). We can plot these points on the coordinate plane and draw a straight line through them to graph the equation 2x+5y=102x + 5y = 10.

3. Final Answer

The table of values is:
x | 0 | 5
y | 2 | 0
The graph is a line passing through the points (0,2) and (5,0).

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