We are given the equation of a line $2x - 3y = 6$. Part (a) asks us to find the values of $A$ and $B$ such that the points $(0, A)$ and $(B, 0)$ lie on the line. Part (b) asks us to identify which of the lines C, D, E, or F corresponds to the given equation $2x - 3y = 6$.

AlgebraLinear EquationsCoordinate GeometryLinesIntercepts
2025/4/30

1. Problem Description

We are given the equation of a line 2x3y=62x - 3y = 6. Part (a) asks us to find the values of AA and BB such that the points (0,A)(0, A) and (B,0)(B, 0) lie on the line. Part (b) asks us to identify which of the lines C, D, E, or F corresponds to the given equation 2x3y=62x - 3y = 6.

2. Solution Steps

(a) To find AA, substitute x=0x = 0 into the equation 2x3y=62x - 3y = 6:
2(0)3y=62(0) - 3y = 6
3y=6-3y = 6
y=63=2y = \frac{6}{-3} = -2
Therefore, A=2A = -2.
To find BB, substitute y=0y = 0 into the equation 2x3y=62x - 3y = 6:
2x3(0)=62x - 3(0) = 6
2x=62x = 6
x=62=3x = \frac{6}{2} = 3
Therefore, B=3B = 3.
(b) The line 2x3y=62x - 3y = 6 has intercepts (0,2)(0, -2) and (3,0)(3, 0). Examining the graph, we can see that line E passes through (0,2)(0, -2) and (3,0)(3, 0).

3. Final Answer

(a) A=2A = -2 and B=3B = 3
(b) Line E

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