We are asked to find the equation of a straight line with a given gradient of 7 that passes through the point (2, 6). We need to express the equation in the form $y = mx + c$, where $m$ is the gradient and $c$ is the y-intercept.

1. Problem Description

We are asked to find the equation of a straight line with a given gradient of 7 that passes through the point (2, 6). We need to express the equation in the form $y = mx + c$, where $m$ is the gradient and $c$ is the y-intercept.

2. Solution Steps

We are given the gradient $m = 7$. The equation of the line is of the form $y = 7x + c$.

We are also given that the line passes through the point (2, 6). This means that when $x = 2$, $y = 6$. We can substitute these values into the equation to find $c$:

$6 = 7(2) + c$

$6 = 14 + c$

$c = 6 - 14$

$c = -8$

Therefore, the equation of the line is $y = 7x - 8$.

3. Final Answer

$y = 7x - 8$