The problem asks us to calculate the area of a door. The door is composed of a rectangle and a semi-circle on top of it. The height of the rectangular part is 2 m and the total height including the semi-circle is 3.2 m. Thus, the radius of the semi-circle is $3.2 - 2 = 1.2$ m. We also need to find the area of the door on a plan with a scale of $1/50$.

GeometryAreaRectangleSemi-circleScaleGeometric ShapesMeasurement
2025/4/30

1. Problem Description

The problem asks us to calculate the area of a door. The door is composed of a rectangle and a semi-circle on top of it. The height of the rectangular part is 2 m and the total height including the semi-circle is 3.2 m. Thus, the radius of the semi-circle is 3.22=1.23.2 - 2 = 1.2 m. We also need to find the area of the door on a plan with a scale of 1/501/50.

2. Solution Steps

a) Calculate the area of the door.
The door consists of a rectangle and a semicircle.
The height of the rectangle is 2 m. The width of the rectangle is equal to the diameter of the semicircle, which is 2×1.2=2.42 \times 1.2 = 2.4 m.
The area of the rectangle is:
Arectangle=height×width=2×2.4=4.8m2A_{rectangle} = height \times width = 2 \times 2.4 = 4.8 m^2
The radius of the semi-circle is r=1.2r = 1.2 m.
The area of a full circle is given by Acircle=πr2A_{circle} = \pi r^2. The area of a semi-circle is half of that:
Asemicircle=12πr2=12π(1.2)2=12π(1.44)=0.72π0.72×3.14162.261952m2A_{semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (1.2)^2 = \frac{1}{2} \pi (1.44) = 0.72 \pi \approx 0.72 \times 3.1416 \approx 2.261952 m^2
The total area of the door is:
Adoor=Arectangle+Asemicircle=4.8+0.72π4.8+2.261952=7.061952m2A_{door} = A_{rectangle} + A_{semicircle} = 4.8 + 0.72\pi \approx 4.8 + 2.261952 = 7.061952 m^2
Rounding to two decimal places, the area of the door is approximately 7.06m27.06 m^2.
b) Calculate the area of the door on a plan with a scale of 1/501/50.
The scale factor for the lengths is 1/501/50.
The scale factor for the areas is (1/50)2=1/2500(1/50)^2 = 1/2500.
The area on the plan is:
Aplan=Adoor×(1/50)2=7.061952/25000.00282478m2A_{plan} = A_{door} \times (1/50)^2 = 7.061952 / 2500 \approx 0.00282478 m^2
Since 1m2=(100cm)2=10000cm21 m^2 = (100 cm)^2 = 10000 cm^2, we have
Aplan=0.00282478×10000=28.2478cm2A_{plan} = 0.00282478 \times 10000 = 28.2478 cm^2.
Rounding to two decimal places, the area is 28.25cm228.25 cm^2.

3. Final Answer

a) The area of the door is approximately 7.06m27.06 m^2.
b) The area of the door on the plan is approximately 28.25cm228.25 cm^2.

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