The problem requires solving equations. The instructions say to pick any 2 from #1-4 and solve those equations. I will solve equation #1 and #2. Equation #1: $\frac{3}{4}(x+20)=9$ Equation #2: $4-2(x-5)-x=-19$

1. Problem Description

The problem requires solving equations. The instructions say to pick any 2 from #1-4 and solve those equations.

I will solve equation #1 and #

2. Equation #1: $\frac{3}{4}(x+20)=9$

Equation #2: $4-2(x-5)-x=-19$

2. Solution Steps

Solving equation #1: $\frac{3}{4}(x+20)=9$

Multiply both sides by 4:

$3(x+20)=36$

Distribute the 3 on the left side:

$3x+60=36$

Subtract 60 from both sides:

$3x=36-60$

$3x=-24$

Divide both sides by 3:

$x=\frac{-24}{3}$

$x=-8$

Solving equation #2: $4-2(x-5)-x=-19$

Distribute the -2 on the left side:

$4-2x+10-x=-19$

Combine like terms on the left side:

$14-3x=-19$

Subtract 14 from both sides:

$-3x=-19-14$

$-3x=-33$

Divide both sides by -3:

$x=\frac{-33}{-3}$

$x=11$

3. Final Answer

The solution to equation #1 is $x=-8$.

The solution to equation #2 is $x=11$.