The image contains several linear equation problems. We are going to solve problem 5 which asks to find the equation of a line that has a slope of $-\frac{4}{5}$ and passes through the point $(-10, 6)$.

1. Problem Description

The image contains several linear equation problems. We are going to solve problem 5 which asks to find the equation of a line that has a slope of $-\frac{4}{5}$ and passes through the point $(-10, 6)$.

2. Solution Steps

We are given the slope $m = -\frac{4}{5}$ and a point $(x_1, y_1) = (-10, 6)$. We can use the point-slope form of a linear equation to find the equation of the line.

The point-slope form of a linear equation is:

$y - y_1 = m(x - x_1)$

Substituting the given values:

$y - 6 = -\frac{4}{5}(x - (-10))$

$y - 6 = -\frac{4}{5}(x + 10)$

Now, we can convert this to slope-intercept form ($y = mx + b$) by solving for $y$:

$y - 6 = -\frac{4}{5}x - \frac{4}{5}(10)$

$y - 6 = -\frac{4}{5}x - 8$

$y = -\frac{4}{5}x - 8 + 6$

$y = -\frac{4}{5}x - 2$

3. Final Answer

The equation of the line is $y = -\frac{4}{5}x - 2$.