We are given a worksheet with angle relationship problems. Problem 1: Two parallel lines A and B are intersected by a transversal. We need to find the measure of each angle. Problem 2: We need to identify the alternate interior angles. We are given that angle 4 is $62^{\circ}$ and we need to find the measure of angle 8, explaining how we know. Problem 3: We are given a triangle with two angles $38^{\circ}$ and $29^{\circ}$. We need to find the measure of angle x. Problem 4: We are given a triangle with two angles $76^{\circ}$ and $45^{\circ}$. We need to find the measure of angle y. Problem 5: $\triangle ABC$ is similar to $\triangle LMN$. $m\angle B = 40^{\circ}$ and $m\angle A = 55^{\circ}$. We need to find $m\angle N$.

GeometryAnglesParallel LinesTransversalsTrianglesAngle Sum PropertySimilar Triangles
2025/4/30

1. Problem Description

We are given a worksheet with angle relationship problems.
Problem 1: Two parallel lines A and B are intersected by a transversal. We need to find the measure of each angle.
Problem 2: We need to identify the alternate interior angles. We are given that angle 4 is 6262^{\circ} and we need to find the measure of angle 8, explaining how we know.
Problem 3: We are given a triangle with two angles 3838^{\circ} and 2929^{\circ}. We need to find the measure of angle x.
Problem 4: We are given a triangle with two angles 7676^{\circ} and 4545^{\circ}. We need to find the measure of angle y.
Problem 5: ABC\triangle ABC is similar to LMN\triangle LMN. mB=40m\angle B = 40^{\circ} and mA=55m\angle A = 55^{\circ}. We need to find mNm\angle N.

2. Solution Steps

Problem 1: Without additional information on the measures of at least one of the angles, we cannot determine the specific measures of all the angles. However, we know that the angles 1, 4, 5, 8 are congruent, and the angles 2, 3, 6, 7 are congruent. Also, any angle from the set (1, 4, 5, 8) is supplementary to any angle from the set (2, 3, 6, 7).
Problem 2: Alternate interior angles are congruent when two parallel lines are intersected by a transversal. In the diagram, angles 4 and 6 are alternate interior angles, and angles 3 and 5 are alternate interior angles. Since line X is parallel to line W, 46\angle 4 \cong \angle 6 and 35\angle 3 \cong \angle 5. We are given that m4=62m\angle 4 = 62^{\circ}. Angles 6 and 8 are supplementary. This means that m6+m8=180m\angle 6 + m\angle 8 = 180^{\circ}. Since m4=m6=62m\angle 4 = m\angle 6 = 62^{\circ}, then 62+m8=18062^{\circ} + m\angle 8 = 180^{\circ}, so m8=18062=118m\angle 8 = 180^{\circ} - 62^{\circ} = 118^{\circ}.
Problem 3: The sum of the angles in a triangle is 180180^{\circ}. Therefore, 38+29+x=18038^{\circ} + 29^{\circ} + x = 180^{\circ}.
67+x=18067^{\circ} + x = 180^{\circ}
x=18067x = 180^{\circ} - 67^{\circ}
x=113x = 113^{\circ}
Problem 4: The sum of the angles in a triangle is 180180^{\circ}. Therefore, 76+45+y=18076^{\circ} + 45^{\circ} + y = 180^{\circ}.
121+y=180121^{\circ} + y = 180^{\circ}
y=180121y = 180^{\circ} - 121^{\circ}
y=59y = 59^{\circ}
Problem 5: Since ABCLMN\triangle ABC \sim \triangle LMN, their corresponding angles are congruent.
mA=mLm\angle A = m\angle L, mB=mMm\angle B = m\angle M, and mC=mNm\angle C = m\angle N.
In ABC\triangle ABC, mA=55m\angle A = 55^{\circ}, mB=40m\angle B = 40^{\circ}, so
mC=180mAmB=1805540=18095=85m\angle C = 180^{\circ} - m\angle A - m\angle B = 180^{\circ} - 55^{\circ} - 40^{\circ} = 180^{\circ} - 95^{\circ} = 85^{\circ}.
Therefore, mN=mC=85m\angle N = m\angle C = 85^{\circ}.

3. Final Answer

Problem 1: Without additional information on the measures of at least one of the angles, we cannot determine the specific measures of all the angles.
Problem 2: m8=118m\angle 8 = 118^{\circ}.
Problem 3: x=113x = 113^{\circ}
Problem 4: y=59y = 59^{\circ}
Problem 5: mN=85m\angle N = 85^{\circ}

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