We are given two points representing the price ($p$) per camera and the quantity ($q$) of cameras supplied per month: $(900, 35)$ and $(1500, 50)$. We need to find the linear supply equation in the form $p = mq + b$, where $m$ is the slope and $b$ is the y-intercept.

AlgebraLinear EquationsSupply EquationSlopeY-intercept
2025/5/2

1. Problem Description

We are given two points representing the price (pp) per camera and the quantity (qq) of cameras supplied per month: (900,35)(900, 35) and (1500,50)(1500, 50). We need to find the linear supply equation in the form p=mq+bp = mq + b, where mm is the slope and bb is the y-intercept.

2. Solution Steps

First, calculate the slope mm using the two given points:
m=p2p1q2q1m = \frac{p_2 - p_1}{q_2 - q_1}
m=50351500900=15600=140=0.025m = \frac{50 - 35}{1500 - 900} = \frac{15}{600} = \frac{1}{40} = 0.025
Now, use the point-slope form of a linear equation:
pp1=m(qq1)p - p_1 = m(q - q_1)
Substitute one of the points (e.g., (900,35)(900, 35)) and the calculated slope mm:
p35=0.025(q900)p - 35 = 0.025(q - 900)
p35=0.025q0.025×900p - 35 = 0.025q - 0.025 \times 900
p35=0.025q22.5p - 35 = 0.025q - 22.5
p=0.025q22.5+35p = 0.025q - 22.5 + 35
p=0.025q+12.5p = 0.025q + 12.5

3. Final Answer

The supply equation is p=0.025q+12.5p = 0.025q + 12.5.

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