The problem asks us to find the total area of two right triangles (A and B). We are given that the units are in meters. We need to find the area of each triangle and add them together. The first triangle has a base of 20 meters and a hypotenuse of 25 meters. The second triangle is similar to the first, so we can assume the dimensions are proportional.

1. Problem Description

The problem asks us to find the total area of two right triangles (A and B). We are given that the units are in meters. We need to find the area of each triangle and add them together. The first triangle has a base of 20 meters and a hypotenuse of 25 meters. The second triangle is similar to the first, so we can assume the dimensions are proportional.

2. Solution Steps

First, let's find the length of the missing side of Triangle B. Let this side be $x$. Since it is a right triangle, we can use the Pythagorean theorem:

$a^2 + b^2 = c^2$

where $a$ and $b$ are the legs of the right triangle, and $c$ is the hypotenuse.

For triangle B, we have:

$20^2 + x^2 = 25^2$

$400 + x^2 = 625$

$x^2 = 625 - 400$

$x^2 = 225$

$x = \sqrt{225} = 15$

So, the missing side of Triangle B (the base of Triangle B) is 15 meters.

Now we can find the area of Triangle B. The area of a triangle is given by:

$Area = (1/2) * base * height$

$Area_B = (1/2) * 15 * 20$

$Area_B = (1/2) * 300$

$Area_B = 150$ square meters.

Next, let's find the area of Triangle A. The height of Triangle A is 4 meters and the base is 3 meters, and the hypotenuse is 5 meters.

Area formula:

$Area = (1/2) * base * height$

$Area_A = (1/2) * 3 * 4 = (1/2) * 12$

$Area_A = 6$ square meters.

Finally, add the areas of the two triangles to get the total area:

$TotalArea = Area_A + Area_B$

$TotalArea = 6 + 150 = 156$ square meters.

3. Final Answer

Triangle A: 6 square meters

Triangle B: 150 square meters

Entire Object: 156 square meters