The problem is to evaluate the expression $(-3)^2 \div (-2) \times (-4)^2$.

ArithmeticOrder of OperationsExponentsMultiplicationDivisionInteger Arithmetic
2025/5/4

1. Problem Description

The problem is to evaluate the expression (3)2÷(2)×(4)2(-3)^2 \div (-2) \times (-4)^2.

2. Solution Steps

We need to follow the order of operations (PEMDAS/BODMAS). First, we evaluate the exponents:
(3)2=(3)×(3)=9(-3)^2 = (-3) \times (-3) = 9
(4)2=(4)×(4)=16(-4)^2 = (-4) \times (-4) = 16
Now we have 9÷(2)×169 \div (-2) \times 16.
Next, we perform division and multiplication from left to right.
9÷(2)=92=4.59 \div (-2) = -\frac{9}{2} = -4.5
Finally, we multiply:
4.5×16=72-4.5 \times 16 = -72

3. Final Answer

-72

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