We are asked to solve the equation $15 \cdot 2^x = 10 \cdot 3^x$ for the value of $x$.

AlgebraExponential EquationsExponentsEquation Solving
2025/5/4

1. Problem Description

We are asked to solve the equation 152x=103x15 \cdot 2^x = 10 \cdot 3^x for the value of xx.

2. Solution Steps

We have the equation 152x=103x15 \cdot 2^x = 10 \cdot 3^x.
First, we can divide both sides by 5 to simplify the coefficients:
32x=23x3 \cdot 2^x = 2 \cdot 3^x.
Next, divide both sides by 3:
2x=233x2^x = \frac{2}{3} \cdot 3^x.
Now divide both sides by 3x3^x:
2x3x=23\frac{2^x}{3^x} = \frac{2}{3}.
We can rewrite the left side as:
(23)x=23\left(\frac{2}{3}\right)^x = \frac{2}{3}.
Since the bases are equal, we can equate the exponents. Thus:
x=1x = 1.

3. Final Answer

The final answer is 1.

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