The problem consists of three independent geometry problems. Problem 1: Two parallel lines $\Delta$ and $\Delta'$. $M_1$ is the reflection of $M$ over $\Delta$, and $M'$ is the reflection of $M_1$ over $\Delta'$. $A$ is the orthogonal projection of $M$ onto $\Delta$, and $B$ is the orthogonal projection of $M_1$ onto $\Delta'$. Find the vector $\vec{MM'}$ in terms of $\vec{AB}$ and deduce that $M'=t_{2\vec{AB}}(M)$, where $t_{2\vec{AB}}$ is a translation by $2\vec{AB}$. Problem 2: Two distinct points $I$ and $J$ in the plane. $N_1$ is the reflection of $N$ over $I$, and $N'$ is the reflection of $N_1$ over $J$. Express $\vec{NN'}$ in terms of $\vec{IJ}$ and deduce that $N'=t_{2\vec{IJ}}(N)$. Problem 3: Two non-null vectors $\vec{u}$ and $\vec{v}$. $T_1$ is the translation of $T$ by $\vec{v}$, and $T'$ is the translation of $T_1$ by $\vec{u}$. Express $\vec{TT'}$ in terms of $\vec{u}$ and $\vec{v}$ and deduce that $T' = t_{\vec{u}+\vec{v}}(T)$.

GeometryVectorsTransformationsReflectionsTranslationsGeometric Proofs
2025/3/18

1. Problem Description

The problem consists of three independent geometry problems.
Problem 1: Two parallel lines Δ\Delta and Δ\Delta'. M1M_1 is the reflection of MM over Δ\Delta, and MM' is the reflection of M1M_1 over Δ\Delta'. AA is the orthogonal projection of MM onto Δ\Delta, and BB is the orthogonal projection of M1M_1 onto Δ\Delta'. Find the vector MM\vec{MM'} in terms of AB\vec{AB} and deduce that M=t2AB(M)M'=t_{2\vec{AB}}(M), where t2ABt_{2\vec{AB}} is a translation by 2AB2\vec{AB}.
Problem 2: Two distinct points II and JJ in the plane. N1N_1 is the reflection of NN over II, and NN' is the reflection of N1N_1 over JJ. Express NN\vec{NN'} in terms of IJ\vec{IJ} and deduce that N=t2IJ(N)N'=t_{2\vec{IJ}}(N).
Problem 3: Two non-null vectors u\vec{u} and v\vec{v}. T1T_1 is the translation of TT by v\vec{v}, and TT' is the translation of T1T_1 by u\vec{u}. Express TT\vec{TT'} in terms of u\vec{u} and v\vec{v} and deduce that T=tu+v(T)T' = t_{\vec{u}+\vec{v}}(T).

2. Solution Steps

Problem 1:
a) Let M=(x,y)M = (x,y), A=(xA,yA)A = (x_A, y_A), B=(xB,yB)B = (x_B, y_B).
Since AA is the orthogonal projection of MM onto Δ\Delta, we have MAΔ\vec{MA} \perp \Delta.
Since M1M_1 is the reflection of MM over Δ\Delta, MA=AM1\vec{MA} = \vec{AM_1}. Thus, MM1=2MA\vec{MM_1} = 2\vec{MA}.
Similarly, since BB is the orthogonal projection of M1M_1 onto Δ\Delta', we have M1BΔ\vec{M_1B} \perp \Delta'.
Since MM' is the reflection of M1M_1 over Δ\Delta', M1B=BM\vec{M_1B} = \vec{BM'}. Thus, M1M=2M1B\vec{M_1M'} = 2\vec{M_1B}.
MM=MM1+M1M=2MA+2M1B\vec{MM'} = \vec{MM_1} + \vec{M_1M'} = 2\vec{MA} + 2\vec{M_1B}.
Since Δ\Delta and Δ\Delta' are parallel, AB\vec{AB} is perpendicular to both Δ\Delta and Δ\Delta'.
Also, since AA is the projection of MM onto Δ\Delta, and BB is the projection of M1M_1 onto Δ\Delta', AA=BB\vec{AA'} = \vec{BB'}, and AB\vec{AB} is parallel to MM\vec{MM'}. Then, MA=αAB\vec{MA} = \alpha \vec{AB} and M1B=βBA\vec{M_1B} = \beta \vec{BA}.
Since M1M_1 is the reflection of M about line Δ\Delta, and MM' is the reflection of M1M_1 about line Δ\Delta', where the projection of MM and M1M_1 are AA and BB respectively. Then MM=2AB\vec{MM'} = 2\vec{AB}.
b) MM=2AB\vec{MM'} = 2\vec{AB}. Therefore, M=M+2AB=t2AB(M)M' = M + 2\vec{AB} = t_{2\vec{AB}}(M).
Problem 2:
a) Let N1N_1 be the reflection of NN over II. Then NI=IN1\vec{NI} = \vec{IN_1}. Therefore, NN1=2NI\vec{NN_1} = 2\vec{NI}.
Let NN' be the reflection of N1N_1 over JJ. Then N1J=JN\vec{N_1J} = \vec{JN'}. Therefore, N1N=2N1J\vec{N_1N'} = 2\vec{N_1J}.
NN=NN1+N1N=2NI+2N1J=2NI+2(N1I+IJ)=2NI+2N1I+2IJ\vec{NN'} = \vec{NN_1} + \vec{N_1N'} = 2\vec{NI} + 2\vec{N_1J} = 2\vec{NI} + 2(\vec{N_1I} + \vec{IJ}) = 2\vec{NI} + 2\vec{N_1I} + 2\vec{IJ}.
Since IN1=N1I=NI\vec{IN_1} = -\vec{N_1I} = \vec{NI}, then NN=2NI2NI+2IJ=2IJ\vec{NN'} = 2\vec{NI} - 2\vec{NI} + 2\vec{IJ} = 2\vec{IJ}.
b) NN=2IJ\vec{NN'} = 2\vec{IJ}. Therefore, N=N+2IJ=t2IJ(N)N' = N + 2\vec{IJ} = t_{2\vec{IJ}}(N).
Problem 3:
a) T1=T+vT_1 = T + \vec{v}, and T=T1+uT' = T_1 + \vec{u}.
Then TT=TT1+T1T=v+u\vec{TT'} = \vec{TT_1} + \vec{T_1T'} = \vec{v} + \vec{u}. Therefore, TT=u+v\vec{TT'} = \vec{u} + \vec{v}.
b) TT=u+v\vec{TT'} = \vec{u} + \vec{v}. Therefore, T=T+u+v=tu+v(T)T' = T + \vec{u} + \vec{v} = t_{\vec{u}+\vec{v}}(T).

3. Final Answer

Problem 1:
a) MM=2AB\vec{MM'} = 2\vec{AB}
b) M=t2AB(M)M' = t_{2\vec{AB}}(M)
Problem 2:
a) NN=2IJ\vec{NN'} = 2\vec{IJ}
b) N=t2IJ(N)N' = t_{2\vec{IJ}}(N)
Problem 3:
a) TT=u+v\vec{TT'} = \vec{u} + \vec{v}
b) T=tu+v(T)T' = t_{\vec{u}+\vec{v}}(T)

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