We are given a frequency distribution table and asked to calculate the geometric mean, harmonic mean, and first quartile. The distribution table shows the mass (in kg) and the corresponding frequency.
Probability and StatisticsDescriptive StatisticsGeometric MeanHarmonic MeanQuartilesFrequency Distribution
2025/5/4
1. Problem Description
We are given a frequency distribution table and asked to calculate the geometric mean, harmonic mean, and first quartile. The distribution table shows the mass (in kg) and the corresponding frequency.
2. Solution Steps
First, we create a table with the midpoints of each class interval and the corresponding frequencies.
Mass (kg) | Frequency (f) | Midpoint (x) | f*x | f*ln(x) | f/x
---|---|---|---|---|---
41-45 | 5 | 43 | 215 | 19.026 | 0.1163
46-50 | 2 | 48 | 96 | 7.746 | 0.0417
51-55 | 6 | 53 | 318 | 24.462 | 0.1132
56-60 | 7 | 58 | 406 | 28.357 | 0.1207
61-65 | 5 | 63 | 315 | 21.892 | 0.0794
66-70 | 3 | 68 | 204 | 12.455 | 0.0441
Total | 28 | | 1554 | 113.938 | 0.5154
1
6. Geometric Mean (G):
The geometric mean is given by:
1
7. Harmonic Mean (H):
The harmonic mean is given by:
1
8. First Quartile ($Q_1$):
The first quartile corresponds to the 25th percentile. We need to find the value below which 25% of the data falls.
Total frequency = 28
25% of 28 = 0.25 * 28 = 7
Cumulative frequencies:
41-45: 5
46-50: 5 + 2 = 7
Since the cumulative frequency reaches 7 at the end of the 46-50 interval, the first quartile falls in this interval.
Where:
L = Lower limit of the first quartile class (46)
N = Total frequency (28)
cf = Cumulative frequency of the class before the first quartile class (5)
f = Frequency of the first quartile class (2)
w = Class width (5)
3. Final Answer
1
6. The geometric mean, G is computed as 58.
5
0
4.
1
7. The harmonic mean, H is computed as 54.
3
2
7.
1
8. The first quartile, $Q_1$ is estimated as
5
1.