We are given a pseudocode and we need to determine the output of the program, which is the value of the variable $a$ printed at the end. The pseudocode initializes $a=5$ and $c=1$. It then enters a loop that repeats until $c > 3$. Inside the loop, $c$ is updated by $c = 2 * c$, and $a$ is updated by $a = a + (2 * c)$. Finally, the program prints the value of $a$.

Discrete MathematicsAlgorithmsIterationPseudocodeProgram Execution
2025/5/5

1. Problem Description

We are given a pseudocode and we need to determine the output of the program, which is the value of the variable aa printed at the end. The pseudocode initializes a=5a=5 and c=1c=1. It then enters a loop that repeats until c>3c > 3. Inside the loop, cc is updated by c=2cc = 2 * c, and aa is updated by a=a+(2c)a = a + (2 * c). Finally, the program prints the value of aa.

2. Solution Steps

Let's trace the values of aa and cc during the execution of the loop.
Initial values:
a=5a = 5
c=1c = 1
First iteration:
c=2c=21=2c = 2 * c = 2 * 1 = 2
a=a+(2c)=5+(22)=5+4=9a = a + (2 * c) = 5 + (2 * 2) = 5 + 4 = 9
Since c=2c=2 is not greater than 33, the loop continues.
Second iteration:
c=2c=22=4c = 2 * c = 2 * 2 = 4
a=a+(2c)=9+(24)=9+8=17a = a + (2 * c) = 9 + (2 * 4) = 9 + 8 = 17
Since c=4c=4 is greater than 33, the loop terminates.
The program then prints the value of aa, which is 1717.

3. Final Answer

17

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