The problem is to solve the following system of inequalities: $4x - 5y \ge 20$ $y < \frac{3}{2}x - 2$

AlgebraInequalitiesSystems of InequalitiesLinear InequalitiesGraphingCoordinate PlaneSolution Region
2025/3/19

1. Problem Description

The problem is to solve the following system of inequalities:
4x5y204x - 5y \ge 20
y<32x2y < \frac{3}{2}x - 2

2. Solution Steps

To solve a system of inequalities, we need to graph each inequality on the same coordinate plane and find the region where the solutions overlap.
Step 1: Graph the first inequality, 4x5y204x - 5y \ge 20.
First, treat the inequality as an equation: 4x5y=204x - 5y = 20.
To find the intercepts, set x=0x=0 and solve for yy: 4(0)5y=204(0) - 5y = 20, which gives 5y=20-5y = 20, so y=4y = -4. The y-intercept is (0,4)(0, -4).
Set y=0y=0 and solve for xx: 4x5(0)=204x - 5(0) = 20, which gives 4x=204x = 20, so x=5x = 5. The x-intercept is (5,0)(5, 0).
Plot these two points (0,4)(0, -4) and (5,0)(5, 0) and draw a straight line through them. Since the inequality is \ge, the line will be solid.
Next, test a point to determine which side of the line to shade. A common point to test is (0,0)(0,0). Plug (0,0)(0,0) into the inequality: 4(0)5(0)204(0) - 5(0) \ge 20, which simplifies to 0200 \ge 20. This is false, so we shade the region that does not contain (0,0)(0,0). In other words, shade below and to the right of the line.
Step 2: Graph the second inequality, y<32x2y < \frac{3}{2}x - 2.
Treat the inequality as an equation: y=32x2y = \frac{3}{2}x - 2. This is in slope-intercept form (y=mx+by = mx + b), where m=32m = \frac{3}{2} is the slope and b=2b = -2 is the y-intercept. The y-intercept is (0,2)(0, -2).
Since the inequality is <<, the line will be dashed (or dotted).
From the y-intercept (0,2)(0, -2), use the slope 32\frac{3}{2} to find another point. Go up 3 units and right 2 units, which gives the point (2,1)(2, 1).
Draw a dashed line through the points (0,2)(0, -2) and (2,1)(2, 1).
Now, test a point to determine which side of the line to shade. Again, use (0,0)(0,0). Plug (0,0)(0,0) into the inequality: 0<32(0)20 < \frac{3}{2}(0) - 2, which simplifies to 0<20 < -2. This is false, so we shade the region that does not contain (0,0)(0,0). In other words, shade below the line.
Step 3: Find the overlapping region.
The solution to the system of inequalities is the region where the shaded areas from both inequalities overlap. Any point in this region is a solution to the system.

3. Final Answer

The solution to the system of inequalities is the region where the graphs of 4x5y204x - 5y \ge 20 and y<32x2y < \frac{3}{2}x - 2 overlap. The graph of 4x5y204x - 5y \ge 20 is a solid line with x-intercept (5,0) and y-intercept (0,-4), shaded below and to the right. The graph of y<32x2y < \frac{3}{2}x - 2 is a dashed line with y-intercept (0,-2) and slope 32\frac{3}{2}, shaded below. The overlapping region is the solution.

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