We need to find the size of angle $p$. The figure shows two lines intersecting at a point. The angles on one side of the intersection are $12^{\circ}$, $21^{\circ}$, and $14^{\circ}$. The angle on the other side of the intersection is $p$.

1. Problem Description

We need to find the size of angle $p$. The figure shows two lines intersecting at a point. The angles on one side of the intersection are $12^{\circ}$, $21^{\circ}$, and $14^{\circ}$. The angle on the other side of the intersection is $p$.

2. Solution Steps

Since the lines intersect, the sum of angles on one side of the intersection point must be equal to the sum of angles on the other side. The sum of the angles on one side is $12^{\circ} + 21^{\circ} + 14^{\circ}$.

$12 + 21 + 14 = 47$

So, the sum is $47^{\circ}$.

Since the angles are equal, $p = 47^{\circ}$.

3. Final Answer

$p = 47^{\circ}$