The task is to determine the output of the given pseudocode. The pseudocode initializes a variable $X$ to 100. Then, a `while` loop iterates as long as $X$ is greater than 95. Inside the loop, the current value of $X$ is printed, and then $X$ is decremented by 1. After the loop finishes, the final value of $X$ is printed.

Discrete MathematicsAlgorithmsPseudocodeLoopsIterationSequences
2025/5/6

1. Problem Description

The task is to determine the output of the given pseudocode. The pseudocode initializes a variable XX to
1
0

0. Then, a `while` loop iterates as long as $X$ is greater than

9

5. Inside the loop, the current value of $X$ is printed, and then $X$ is decremented by

1. After the loop finishes, the final value of $X$ is printed.

2. Solution Steps

The initial value of XX is
1
0

0. The `while` loop condition is $X > 95$.

Iteration 1:
X=100X = 100. The condition 100>95100 > 95 is true.
Print X=100X = 100.
X=1001=99X = 100 - 1 = 99.
Iteration 2:
X=99X = 99. The condition 99>9599 > 95 is true.
Print X=99X = 99.
X=991=98X = 99 - 1 = 98.
Iteration 3:
X=98X = 98. The condition 98>9598 > 95 is true.
Print X=98X = 98.
X=981=97X = 98 - 1 = 97.
Iteration 4:
X=97X = 97. The condition 97>9597 > 95 is true.
Print X=97X = 97.
X=971=96X = 97 - 1 = 96.
Iteration 5:
X=96X = 96. The condition 96>9596 > 95 is true.
Print X=96X = 96.
X=961=95X = 96 - 1 = 95.
The loop terminates because the condition 95>9595 > 95 is false.
After the loop, the value of XX is
9

5. Print $X = 95$.

The printed output is 100, 99, 98, 97, 96,
9
5.

3. Final Answer

(2) 100,99,98,97,96,95

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