The problem asks whether the region where $y > 3x + 4$ should be shaded above or below the line $y = 3x + 4$. We are given that the point $(3, -4)$ lies below the line $y=3x+4$.

AlgebraLinear InequalitiesGraphingTest Point Method
2025/3/6

1. Problem Description

The problem asks whether the region where y>3x+4y > 3x + 4 should be shaded above or below the line y=3x+4y = 3x + 4. We are given that the point (3,4)(3, -4) lies below the line y=3x+4y=3x+4.

2. Solution Steps

Since we want to graph the region where y>3x+4y > 3x + 4, we need to determine which side of the line to shade. We can use the point (3,4)(3, -4) as a test point. If (3,4)(3, -4) satisfies the inequality y>3x+4y > 3x + 4, then we would shade the region containing (3,4)(3, -4). Otherwise, we shade the region on the other side of the line.
Substitute x=3x = 3 and y=4y = -4 into the inequality y>3x+4y > 3x + 4:
4>3(3)+4-4 > 3(3) + 4
4>9+4-4 > 9 + 4
4>13-4 > 13
This statement is false. Therefore, the point (3,4)(3, -4) does not satisfy the inequality y>3x+4y > 3x + 4. Since (3,4)(3, -4) lies below the line, and it does not satisfy the inequality, we should shade the region above the line.

3. Final Answer

Above the line

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