The problem describes a scenario where a computer can be purchased for N$10,500.00 in cash, or through a hire purchase agreement requiring a 10% deposit and monthly installments of 0.5% of the remaining amount plus N$250. The problem asks us to calculate: (a) the deposit amount, (b) the monthly instalment, (c) the duration of the installment plan if the total hire purchase price is N$10,849.63, and (d) the percentage difference between the amount paid and the cash price.

Applied MathematicsFinancial MathematicsPercentageInstallment PlansArithmetic
2025/5/7

1. Problem Description

The problem describes a scenario where a computer can be purchased for N10,500.00incash,orthroughahirepurchaseagreementrequiringa1010,500.00 in cash, or through a hire purchase agreement requiring a 10% deposit and monthly installments of 0.5% of the remaining amount plus N
2
5

0. The problem asks us to calculate: (a) the deposit amount, (b) the monthly instalment, (c) the duration of the installment plan if the total hire purchase price is N$10,849.63, and (d) the percentage difference between the amount paid and the cash price.

2. Solution Steps

(a) The deposit:
The deposit is 10% of the cash price, which is N$10,500.
0

0. $Deposit = (10/100) * 10500 = 1050$

(b) Monthly installment:
First, we need to find the remaining amount after the deposit is paid.
RemainingAmount=CashPriceDeposit=105001050=9450RemainingAmount = CashPrice - Deposit = 10500 - 1050 = 9450
The monthly installment is 0.5% of the remaining amount plus N$
2
5

0. $MonthlyInstallment = (0.5/100) * RemainingAmount + 250 = (0.005 * 9450) + 250 = 47.25 + 250 = 297.25$

(c) Duration of installment plan:
The total payment for hire purchase is N$10,849.
6

3. The deposit paid is N$1,

0
5

0. $TotalInstallmentAmount = TotalPayment - Deposit = 10849.63 - 1050 = 9799.63$

Each monthly installment is N$297.
2

5. $NumberOfInstallments = TotalInstallmentAmount / MonthlyInstallment = 9799.63 / 297.25 \approx 32.96$

Since we cannot have a fraction of a month, let's consider that it is approximately 33 months.
Number of years =33/12=2.75= 33 / 12 = 2.75 years. So, 2 years and 0.75×12=90.75 \times 12 = 9 months.
So, the installments last for 2 years and 9 months.
Note that 33×297.25=9700+2973=9819.2533 \times 297.25 = 9700+297*3 = 9819.25 this shows that the calculation does not match exactly with the given data. Let's denote the exact number of months by n. Then 1050+n(0.005(105001050)+250)=10849.631050+ n(0.005(10500-1050)+250)=10849.63, 1050+n(47.25+250)=10849.631050 + n(47.25+250) = 10849.63, 1050+n(297.25)=10849.631050 + n(297.25) = 10849.63.
Then 297.25n=9799.63297.25n = 9799.63 and n=9799.63/297.25=32.9633n = 9799.63 / 297.25 = 32.96 \approx 33 months.
33 months=2 years and 9 months=2 years, 9 months and 0 weeks33 \text{ months} = 2 \text{ years and } 9 \text{ months} = 2 \text{ years, } 9 \text{ months and } 0 \text{ weeks}.
(d) Percentage difference between the amount paid and the cash price:
Difference=TotalPaymentCashPrice=10849.6310500=349.63Difference = TotalPayment - CashPrice = 10849.63 - 10500 = 349.63
PercentageDifference=(Difference/CashPrice)100=(349.63/10500)1003.33%PercentageDifference = (Difference / CashPrice) * 100 = (349.63 / 10500) * 100 \approx 3.33\%

3. Final Answer

(a) The deposit is N$1050.
0

0. (b) The monthly installment is N$297.

2

5. (c) The installment lasts for 2 years, 9 months and 0 weeks.

(d) The percentage difference is 3.33%.

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