The problem describes a cylinder with diameter $d = 10$ cm and length (height) $h = 38$ cm. We need to find: (a) The circumference of the base. (b) The volume of the cylinder. (c) The area of the base. We are then asked to find the total surface area of a similar cylinder.

GeometryCylinderCircumferenceVolumeSurface AreaArea
2025/3/19

1. Problem Description

The problem describes a cylinder with diameter d=10d = 10 cm and length (height) h=38h = 38 cm. We need to find:
(a) The circumference of the base.
(b) The volume of the cylinder.
(c) The area of the base.
We are then asked to find the total surface area of a similar cylinder.

2. Solution Steps

(a) The circumference of the base is given by the formula:
C=πdC = \pi d
C=π(10)C = \pi (10)
C=10πC = 10\pi cm
Assuming we want an approximate answer, use π3.14159\pi \approx 3.14159:
C10×3.14159=31.4159C \approx 10 \times 3.14159 = 31.4159 cm
(b) The volume of the cylinder is given by the formula:
V=πr2hV = \pi r^2 h
Where rr is the radius and hh is the height. Since d=10d = 10, r=d/2=10/2=5r = d/2 = 10/2 = 5 cm.
V=π(52)(38)V = \pi (5^2) (38)
V=π(25)(38)V = \pi (25) (38)
V=950πV = 950\pi cm3^3
Assuming we want an approximate answer, use π3.14159\pi \approx 3.14159:
V950×3.14159=2984.5105V \approx 950 \times 3.14159 = 2984.5105 cm3^3
(c) The area of the base is given by the formula:
A=πr2A = \pi r^2
A=π(52)A = \pi (5^2)
A=25πA = 25\pi cm2^2
Assuming we want an approximate answer, use π3.14159\pi \approx 3.14159:
A25×3.14159=78.53975A \approx 25 \times 3.14159 = 78.53975 cm2^2
The problem then asks us to calculate the total surface area of the similar cylinder. The total surface area of a cylinder is:
SA=2πrh+2πr2=2πr(h+r)SA = 2\pi r h + 2\pi r^2 = 2\pi r (h + r)
For this cylinder:
SA=2π(5)(38+5)=10π(43)=430πSA = 2\pi (5) (38+5) = 10\pi (43) = 430\pi cm2^2
Assuming we want an approximate answer, use π3.14159\pi \approx 3.14159:
SA430×3.14159=1350.8837SA \approx 430 \times 3.14159 = 1350.8837 cm2^2

3. Final Answer

(a) The circumference of the base is 10π10\pi cm (approximately 31.4231.42 cm).
(b) The volume of the cylinder is 950π950\pi cm3^3 (approximately 2984.512984.51 cm3^3).
(c) The area of the base is 25π25\pi cm2^2 (approximately 78.5478.54 cm2^2).
The total surface area is 430π430\pi cm2^2 (approximately 1350.881350.88 cm2^2).

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