The problem asks to expand the expression $(2a-b)(1+c)$.

AlgebraPolynomial ExpansionAlgebraic Manipulation
2025/5/8

1. Problem Description

The problem asks to expand the expression (2ab)(1+c)(2a-b)(1+c).

2. Solution Steps

We need to multiply each term in the first parentheses by each term in the second parentheses.
(2ab)(1+c)=2a(1+c)b(1+c)(2a-b)(1+c) = 2a(1+c) -b(1+c)
Now, we distribute 2a2a and b-b into the parentheses.
2a(1+c)=2a(1)+2a(c)=2a+2ac2a(1+c) = 2a(1) + 2a(c) = 2a + 2ac
b(1+c)=b(1)b(c)=bbc-b(1+c) = -b(1) - b(c) = -b -bc
Combine the results:
2a+2acbbc2a + 2ac - b - bc

3. Final Answer

2a+2acbbc2a + 2ac - b - bc

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