The problem asks us to determine the number of moles of sodium hydroxide (NaOH) present in 2.5g of the compound. The atomic masses are given as H=1, O=16, and Na=23.

1. Problem Description

The problem asks us to determine the number of moles of sodium hydroxide (NaOH) present in 2.5g of the compound. The atomic masses are given as H=1, O=16, and Na=

2

3.

2. Solution Steps

First, we need to calculate the molar mass of NaOH.

Molar mass of NaOH = (Atomic mass of Na) + (Atomic mass of O) + (Atomic mass of H)

$M_{NaOH} = 23 + 16 + 1 = 40 \, g/mol$

Next, we will calculate the number of moles of NaOH in 2.5g of NaOH using the formula:

Number of moles = (Given mass) / (Molar mass)

$n = \frac{m}{M}$

$n = \frac{2.5 \, g}{40 \, g/mol}$

$n = 0.0625 \, mol$

3. Final Answer

The number of moles of sodium hydroxide (NaOH) in 2.5g of NaOH is 0.0625 moles.