We need to complete the ANOVA table for a simple linear regression. We are given the following information: - SS(Model) = 44.21 - SS(Total) = 66.12 - df(Total) = 44 We need to find: - SS(Error) - df(Model) - df(Error) - MS(Model) - MS(Error) - F

Probability and StatisticsANOVALinear RegressionStatistical AnalysisF-statisticDegrees of FreedomSum of SquaresMean Square
2025/5/8

1. Problem Description

We need to complete the ANOVA table for a simple linear regression. We are given the following information:
- SS(Model) = 44.21
- SS(Total) = 66.12
- df(Total) = 44
We need to find:
- SS(Error)
- df(Model)
- df(Error)
- MS(Model)
- MS(Error)
- F

2. Solution Steps

First, we calculate SS(Error).
SSTotal=SSModel+SSErrorSS_{Total} = SS_{Model} + SS_{Error}
SSError=SSTotalSSModelSS_{Error} = SS_{Total} - SS_{Model}
SSError=66.1244.21=21.91SS_{Error} = 66.12 - 44.21 = 21.91
Next, we find df(Model). For a simple linear regression, the degrees of freedom for the model is always

1. $df_{Model} = 1$

Then we find df(Error).
dfTotal=dfModel+dfErrordf_{Total} = df_{Model} + df_{Error}
dfError=dfTotaldfModeldf_{Error} = df_{Total} - df_{Model}
dfError=441=43df_{Error} = 44 - 1 = 43
Now we calculate MS(Model).
MSModel=SSModeldfModelMS_{Model} = \frac{SS_{Model}}{df_{Model}}
MSModel=44.211=44.21MS_{Model} = \frac{44.21}{1} = 44.21
We calculate MS(Error).
MSError=SSErrordfErrorMS_{Error} = \frac{SS_{Error}}{df_{Error}}
MSError=21.91430.51MS_{Error} = \frac{21.91}{43} \approx 0.51
Finally, we calculate the F statistic.
F=MSModelMSErrorF = \frac{MS_{Model}}{MS_{Error}}
F=44.210.5186.69F = \frac{44.21}{0.51} \approx 86.69

3. Final Answer

Source | SS | df | MS | F
-------|-------|----|--------|--------
Model | 44.21 | 1 | 44.21 | 86.69
Error | 21.91 | 43 | 0.51 |
Total | 66.12 | 44 | |

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