The problem asks us to calculate the force exerted on the piston of a diesel engine during combustion. The diameter of the piston is given as $d = 800 \text{ mm}$, and the pressure during combustion is $P = 20 \text{ bar}$. We are provided with the formula $A = \frac{\pi \cdot d^2}{4}$ which represents the area of the piston.

Applied MathematicsPhysicsForce CalculationArea CalculationUnits ConversionEngineering
2025/5/10

1. Problem Description

The problem asks us to calculate the force exerted on the piston of a diesel engine during combustion. The diameter of the piston is given as d=800 mmd = 800 \text{ mm}, and the pressure during combustion is P=20 barP = 20 \text{ bar}. We are provided with the formula A=πd24A = \frac{\pi \cdot d^2}{4} which represents the area of the piston.

2. Solution Steps

First, we need to convert the diameter from millimeters to meters:
d=800 mm=0.8 md = 800 \text{ mm} = 0.8 \text{ m}.
Next, calculate the area of the piston using the given formula:
A=πd24=π(0.8)24=π0.644=0.16π m2A = \frac{\pi \cdot d^2}{4} = \frac{\pi \cdot (0.8)^2}{4} = \frac{\pi \cdot 0.64}{4} = 0.16\pi \text{ m}^2.
Now we need to convert the pressure from bar to Pascals (Pa), where 1 bar = 10510^5 Pa:
P=20 bar=20105 Pa=2106 PaP = 20 \text{ bar} = 20 \cdot 10^5 \text{ Pa} = 2 \cdot 10^6 \text{ Pa}.
The force FF exerted on the piston is given by the formula:
F=PAF = P \cdot A.
Substituting the values we have:
F=(2106 Pa)(0.16π m2)=0.32π106 N=320000π NF = (2 \cdot 10^6 \text{ Pa}) \cdot (0.16\pi \text{ m}^2) = 0.32\pi \cdot 10^6 \text{ N} = 320000\pi \text{ N}.
Approximating π\pi as 3.141593.14159:
F3200003.14159 N1005308.8 NF \approx 320000 \cdot 3.14159 \text{ N} \approx 1005308.8 \text{ N}.

3. Final Answer

The force exerted on the piston is approximately 1005308.81005308.8 N.

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