The problem asks us to find the size of angle $ABC$ in a triangle $ABC$, where angle $BAC$ is $72^\circ$ and angle $BCA$ is $37^\circ$.

1. Problem Description

The problem asks us to find the size of angle $ABC$ in a triangle $ABC$, where angle $BAC$ is $72^\circ$ and angle $BCA$ is $37^\circ$.

2. Solution Steps

To find the size of angle $ABC$, we can use the fact that the sum of angles in a triangle is $180^\circ$. Therefore,

$Angle ABC + Angle BAC + Angle BCA = 180^\circ$

$Angle ABC + 72^\circ + 37^\circ = 180^\circ$

$Angle ABC + 109^\circ = 180^\circ$

$Angle ABC = 180^\circ - 109^\circ$

$Angle ABC = 71^\circ$

3. Final Answer

The size of angle $ABC$ is $71^\circ$.