We are given a quadrilateral $ABCD$ with $\angle ADC = 96^\circ$, $\angle BCD = 90^\circ$ (right angle), and $\angle ABC = 67^\circ$. We need to find the size of angle $DAB$, which is $\angle A$.

1. Problem Description

We are given a quadrilateral $ABCD$ with $\angle ADC = 96^\circ$, $\angle BCD = 90^\circ$ (right angle), and $\angle ABC = 67^\circ$. We need to find the size of angle $DAB$, which is $\angle A$.

2. Solution Steps

The sum of the interior angles of a quadrilateral is $360^\circ$.

Therefore, we have

$\angle A + \angle B + \angle C + \angle D = 360^\circ$

Substituting the given angles, we get:

$\angle A + 67^\circ + 90^\circ + 96^\circ = 360^\circ$

$\angle A + 253^\circ = 360^\circ$

$\angle A = 360^\circ - 253^\circ$

$\angle A = 107^\circ$

3. Final Answer

The size of angle $DAB$ is $107^\circ$.