We are given a triangle ABD with angles $14^\circ$ at B, $62^\circ$ at A, and $31^\circ$ at D. We want to find the size of the reflex angle BCD.

GeometryTrianglesAnglesAngle CalculationReflex Angle
2025/5/11

1. Problem Description

We are given a triangle ABD with angles 1414^\circ at B, 6262^\circ at A, and 3131^\circ at D. We want to find the size of the reflex angle BCD.

2. Solution Steps

First, we need to find the angle CBD. Since the sum of angles in triangle ABD is 180180^\circ, we have:
14+62+31+ADB=18014^\circ + 62^\circ + 31^\circ + \angle ADB = 180^\circ
ADB=180(14+62+31)\angle ADB = 180^\circ - (14^\circ + 62^\circ + 31^\circ)
ADB=180107=73\angle ADB = 180^\circ - 107^\circ = 73^\circ
Therefore, ADB=73\angle ADB = 73^\circ.
Next, we can find BCD\angle BCD. The angles BCD\angle BCD and ADB\angle ADB must be supplementary, meaning they add to 180180^\circ. Thus,
BCD=180ADB\angle BCD = 180^\circ - \angle ADB
BCD=18073=107\angle BCD = 180^\circ - 73^\circ = 107^\circ
Finally, we need to find the reflex angle BCD. A reflex angle is an angle greater than 180180^\circ but less than 360360^\circ. The reflex angle BCD is given by:
Reflex BCD=360BCD\angle BCD = 360^\circ - \angle BCD
Reflex BCD=360107=253\angle BCD = 360^\circ - 107^\circ = 253^\circ

3. Final Answer

The size of the reflex angle BCD is 253253^\circ.

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