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Callum, Steph, and Adam sold a total of 42 games. The ratio of games sold by Callum, Steph, and Adam is $2:4:1$. The problem asks how many more games Steph sold than Adam.

ArithmeticRatio and ProportionWord ProblemProblem Solving
2025/5/12

1. Problem Description

Callum, Steph, and Adam sold a total of 42 games. The ratio of games sold by Callum, Steph, and Adam is 2:4:12:4:1. The problem asks how many more games Steph sold than Adam.

2. Solution Steps

First, find the total ratio by summing the individual ratios.
Total ratio =2+4+1=7= 2 + 4 + 1 = 7
Next, determine the value of one ratio unit by dividing the total number of games by the total ratio.
Value of one ratio unit =427=6= \frac{42}{7} = 6
Now, calculate the number of games sold by Steph.
Steph's games =4×6=24= 4 \times 6 = 24
Next, calculate the number of games sold by Adam.
Adam's games =1×6=6= 1 \times 6 = 6
Finally, find the difference between the number of games sold by Steph and Adam.
Difference =Steph’s games−Adam’s games=24−6=18= \text{Steph's games} - \text{Adam's games} = 24 - 6 = 18

3. Final Answer

Steph sold 18 more games than Adam.

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