The problem states that $P$ and $Q$ are subsets of a universal set. We need to find the value of $(P \cup Q) \cap Q$.

Discrete MathematicsSet TheorySet OperationsUnionIntersectionAbsorption Law
2025/5/12

1. Problem Description

The problem states that PP and QQ are subsets of a universal set. We need to find the value of (PQ)Q(P \cup Q) \cap Q.

2. Solution Steps

We can use the distributive property of sets. However, a simpler approach is to use the absorption law.
We are given (PQ)Q(P \cup Q) \cap Q.
A(AB)=AA \cap (A \cup B) = A
A(AB)=AA \cup (A \cap B) = A
Let A=QA = Q and B=PB = P.
(PQ)Q=Q(PQ)(P \cup Q) \cap Q = Q \cap (P \cup Q)
By the commutative property of union, PQ=QPP \cup Q = Q \cup P.
Therefore, Q(PQ)=Q(QP)Q \cap (P \cup Q) = Q \cap (Q \cup P).
Using the absorption law: A(AB)=AA \cap (A \cup B) = A, we have
Q(QP)=QQ \cap (Q \cup P) = Q.
Alternatively:
The union of P and Q, PQP \cup Q, contains all elements in P as well as all elements in Q. The intersection of this union with Q, (PQ)Q(P \cup Q) \cap Q, would contain all elements that are in both (PQ)(P \cup Q) and Q. Since all elements in Q are already in (PQ)(P \cup Q), the intersection is simply Q.

3. Final Answer

Q

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