A body of mass $10 kg$ is lifted to a height of $10 m$. The average value of gravity is $g = 10 m/s^2$. We need to calculate the work done.

Applied MathematicsWorkPhysicsMechanicsEnergyUnitsFormula Application
2025/5/12

1. Problem Description

A body of mass 10kg10 kg is lifted to a height of 10m10 m. The average value of gravity is g=10m/s2g = 10 m/s^2. We need to calculate the work done.

2. Solution Steps

The work done WW in lifting an object is given by the formula:
W=mghW = mgh
where:
mm is the mass of the object,
gg is the acceleration due to gravity, and
hh is the height to which the object is lifted.
We are given:
m=10kgm = 10 kg
g=10m/s2g = 10 m/s^2
h=10mh = 10 m
Plugging in the given values, we get:
W=(10kg)(10m/s2)(10m)W = (10 kg) * (10 m/s^2) * (10 m)
W=1000kgm2/s2W = 1000 kg \cdot m^2/s^2
W=1000JW = 1000 J

3. Final Answer

The work done is 1000J1000 J.

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