The problem asks us to find three consecutive integers that sum up to 6.

1. Problem Description

The problem asks us to find three consecutive integers that sum up to

6.

2. Solution Steps

Let the three consecutive integers be $n$, $n+1$, and $n+2$.

Their sum is $n + (n+1) + (n+2) = 6$.

Combine like terms: $3n + 3 = 6$.

Subtract 3 from both sides: $3n = 6 - 3$, which simplifies to $3n = 3$.

Divide both sides by 3: $n = 3 / 3$, which simplifies to $n = 1$.

The three consecutive integers are $n=1$, $n+1=1+1=2$, and $n+2=1+2=3$.

We can check that $1 + 2 + 3 = 6$.

3. Final Answer

The three consecutive integers are 1, 2, and 3.