The problem asks us to find four consecutive integers that add up to 206.

1. Problem Description

The problem asks us to find four consecutive integers that add up to

2

0

6.

2. Solution Steps

Let the first integer be $x$. Then the next three consecutive integers will be $x+1$, $x+2$, and $x+3$.

The sum of these four integers is $x + (x+1) + (x+2) + (x+3)$. We are given that this sum equals

2

0

6. Therefore, we can set up the equation:

$x + (x+1) + (x+2) + (x+3) = 206$

Combining like terms, we have:

$4x + 6 = 206$

Subtract 6 from both sides:

$4x = 200$

Divide both sides by 4:

$x = 50$

So, the first integer is

5

0. The other three integers are:

$x+1 = 50+1 = 51$

$x+2 = 50+2 = 52$

$x+3 = 50+3 = 53$

The four consecutive integers are 50, 51, 52, and

5

3. Let's check the sum: $50 + 51 + 52 + 53 = 206$.

3. Final Answer

50, 51, 52, 53