The problem asks us to find four consecutive odd integers that add up to 88.

AlgebraLinear EquationsInteger PropertiesConsecutive Integers
2025/5/12

1. Problem Description

The problem asks us to find four consecutive odd integers that add up to
8
8.

2. Solution Steps

Let the first odd integer be xx. Since the integers are consecutive and odd, the next three integers will be x+2x+2, x+4x+4, and x+6x+6.
The sum of these four integers is 88, so we can write the equation:
x+(x+2)+(x+4)+(x+6)=88x + (x+2) + (x+4) + (x+6) = 88
Combine like terms:
4x+12=884x + 12 = 88
Subtract 12 from both sides:
4x=88124x = 88 - 12
4x=764x = 76
Divide both sides by 4:
x=764x = \frac{76}{4}
x=19x = 19
Now we can find the four consecutive odd integers:
First integer: x=19x = 19
Second integer: x+2=19+2=21x+2 = 19+2 = 21
Third integer: x+4=19+4=23x+4 = 19+4 = 23
Fourth integer: x+6=19+6=25x+6 = 19+6 = 25
Therefore, the four consecutive odd integers are 19, 21, 23, and
2
5.

3. Final Answer

19, 21, 23, 25

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