The problem states that the sum of four consecutive even integers is 220. We need to find these four integers.

1. Problem Description

The problem states that the sum of four consecutive even integers is

2

2

0. We need to find these four integers.

2. Solution Steps

Let $x$ be the first even integer. Then the next three consecutive even integers are $x+2$, $x+4$, and $x+6$.

The sum of these four integers is given as 220, so we have the equation:

$x + (x+2) + (x+4) + (x+6) = 220$

Combine the like terms:

$4x + 12 = 220$

Subtract 12 from both sides:

$4x = 220 - 12$

$4x = 208$

Divide both sides by 4:

$x = \frac{208}{4}$

$x = 52$

So the first even integer is

5

2. The next three are:

$x+2 = 52+2 = 54$

$x+4 = 52+4 = 56$

$x+6 = 52+6 = 58$

The four consecutive even integers are 52, 54, 56, and

5

8.

3. Final Answer

The four consecutive even integers are 52, 54, 56, and 58.