Given two vectors $u = i + 3j + k$ and $v = 4i + 7j$, the problem is to find the cross product $u \times v$.

GeometryVectorsCross Product3D Geometry
2025/3/7

1. Problem Description

Given two vectors u=i+3j+ku = i + 3j + k and v=4i+7jv = 4i + 7j, the problem is to find the cross product u×vu \times v.

2. Solution Steps

The cross product of two vectors u=u1i+u2j+u3ku = u_1i + u_2j + u_3k and v=v1i+v2j+v3kv = v_1i + v_2j + v_3k is given by:
u×v=(u2v3u3v2)i(u1v3u3v1)j+(u1v2u2v1)ku \times v = (u_2v_3 - u_3v_2)i - (u_1v_3 - u_3v_1)j + (u_1v_2 - u_2v_1)k
Here, u=i+3j+ku = i + 3j + k, which means u1=1u_1 = 1, u2=3u_2 = 3, and u3=1u_3 = 1.
And v=4i+7jv = 4i + 7j, which means v1=4v_1 = 4, v2=7v_2 = 7, and v3=0v_3 = 0.
Using the formula for the cross product:
u×v=(3(0)1(7))i(1(0)1(4))j+(1(7)3(4))ku \times v = (3(0) - 1(7))i - (1(0) - 1(4))j + (1(7) - 3(4))k
u×v=(07)i(04)j+(712)ku \times v = (0 - 7)i - (0 - 4)j + (7 - 12)k
u×v=7i+4j5ku \times v = -7i + 4j - 5k

3. Final Answer

u×v=7i+4j5ku \times v = -7i + 4j - 5k

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