The problem has two parts: 7. Calculate the arc length of two arcs given their radii and the central angle. a) Find the arc length of arc $CB$ if the radius is $7$ meters. (The central angle associated with $CB$ is $42^\circ$ from the diagram with arc $LN$.) b) Find the arc length of arc $EAB$ if the radius is $20$ millimeters. (The central angle associated with $EAB$ is $42^\circ$ from the diagram with arc $LN$.) 8. Find the measures of three angles in a circle. (The angles are $m\angle H$, $m\angle F$, and $m\angle G$.)

GeometryArc LengthCirclesAnglesRadians
2025/5/13

1. Problem Description

The problem has two parts:

7. Calculate the arc length of two arcs given their radii and the central angle.

a) Find the arc length of arc CBCB if the radius is 77 meters. (The central angle associated with CBCB is 4242^\circ from the diagram with arc LNLN.)
b) Find the arc length of arc EABEAB if the radius is 2020 millimeters. (The central angle associated with EABEAB is 4242^\circ from the diagram with arc LNLN.)

8. Find the measures of three angles in a circle. (The angles are $m\angle H$, $m\angle F$, and $m\angle G$.)

2. Solution Steps

7. The formula for the arc length $s$ is given by $s = r \theta$, where $r$ is the radius and $\theta$ is the central angle in radians.

a) Given r=7r = 7 meters and the central angle is 4242^\circ, we first convert the angle to radians: θ=42×π180=42π180=7π30\theta = 42^\circ \times \frac{\pi}{180^\circ} = \frac{42\pi}{180} = \frac{7\pi}{30} radians.
Then, the arc length s=7×7π30=49π305.13127s = 7 \times \frac{7\pi}{30} = \frac{49\pi}{30} \approx 5.13127 meters. Rounding to the nearest hundredth, we get 5.135.13 meters.
b) Given r=20r = 20 millimeters and the central angle is 4242^\circ, we first convert the angle to radians: θ=42×π180=42π180=7π30\theta = 42^\circ \times \frac{\pi}{180^\circ} = \frac{42\pi}{180} = \frac{7\pi}{30} radians.
Then, the arc length s=20×7π30=140π30=14π314.66076s = 20 \times \frac{7\pi}{30} = \frac{140\pi}{30} = \frac{14\pi}{3} \approx 14.66076 millimeters. Rounding to the nearest hundredth, we get 14.6614.66 millimeters.

8. From the given circle diagram, we have:

a) F\angle F is the central angle and H\angle H is an inscribed angle that intercepts the same arc as F\angle F. Therefore, mH=12mFm\angle H = \frac{1}{2} m\angle F. Without further information on the measure of F\angle F, we cannot calculate mHm\angle H. Looking at the diagram and assuming F\angle F intercepts 180180^\circ, then mF=90m\angle F = 90^\circ and thus mH=45m\angle H = 45^\circ.
b) If F\angle F intercepts 180180^\circ, then mF=90m\angle F = 90^\circ.
c) G\angle G is the exterior angle and is congruent with F\angle F, therefore mG=F=90m\angle G = \angle F = 90^\circ.

3. Final Answer

7.

a) 5.135.13 meters
b) 14.6614.66 millimeters

8.

a) 4545^\circ
b) 9090^\circ
c) 9090^\circ

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