We are given a circle with a triangle inscribed in it. One angle of the triangle is given as $95^\circ$. The angles are labeled $a$, $b$, and $c$. Also, it is indicated that two sides of the triangle are equal in length, which means the triangle is isosceles. We need to find the measures of angles $a$, $b$, and $c$. Angle $a$ is given as $95^\circ$, which seems to be an error given the figure. We will assume the $95^{\circ}$ angle is angle $a$. The side opposite angle $a$ is the diameter of the circle, therefore $a$ is a right angle, and $a = 90^\circ$.

GeometryTrianglesAnglesIsosceles TriangleCirclesInscribed Angle
2025/5/13

1. Problem Description

We are given a circle with a triangle inscribed in it. One angle of the triangle is given as 9595^\circ. The angles are labeled aa, bb, and cc. Also, it is indicated that two sides of the triangle are equal in length, which means the triangle is isosceles. We need to find the measures of angles aa, bb, and cc. Angle aa is given as 9595^\circ, which seems to be an error given the figure. We will assume the 9595^{\circ} angle is angle aa. The side opposite angle aa is the diameter of the circle, therefore aa is a right angle, and a=90a = 90^\circ.

2. Solution Steps

Since the side opposite angle aa is the diameter of the circle, the angle aa is a right angle. Therefore, a=90a = 90^\circ.
The sum of angles in a triangle is 180180^\circ.
a+b+c=180a + b + c = 180^\circ
Since a=90a = 90^\circ, we have
90+b+c=18090^\circ + b + c = 180^\circ
b+c=18090b + c = 180^\circ - 90^\circ
b+c=90b + c = 90^\circ
The two sides of the triangle are equal. This means that the angles opposite these sides are equal, so b=cb = c.
Therefore, we can substitute bb for cc:
b+b=90b + b = 90^\circ
2b=902b = 90^\circ
b=902b = \frac{90^\circ}{2}
b=45b = 45^\circ
Since b=cb = c, then c=45c = 45^\circ.

3. Final Answer

a=90a = 90^\circ
b=45b = 45^\circ
c=45c = 45^\circ

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