We are given a circle with center W. Two chords, YZ and UX, intersect at point V. We are given the following information: $YZ = 17$, $UX = 11$, and $m\angle UX = 80.6^\circ$. We need to find the length of $UV$, the measure of arc $UY$, and the length of $VW$.

GeometryCircle GeometryChordsAngles in a CircleArc MeasureGeometric Proofs
2025/5/13

1. Problem Description

We are given a circle with center W. Two chords, YZ and UX, intersect at point V. We are given the following information: YZ=17YZ = 17, UX=11UX = 11, and mUX=80.6m\angle UX = 80.6^\circ. We need to find the length of UVUV, the measure of arc UYUY, and the length of VWVW.

2. Solution Steps

a) Find the length of UVUV.
Since the chords UZUZ and YZYZ intersect, and we know YZ=17YZ = 17 and UX=11UX = 11, and also that they intersect at a right angle, we can use the property that if two chords intersect at a point, then the product of the segments of one chord is equal to the product of the segments of the other chord. Since UVY\angle UVY is a right angle (90 degrees), UV2+VY2=UY2UV^2 + VY^2 = UY^2 and VX2+VZ2=XZ2VX^2 + VZ^2 = XZ^2. However, this information is not helpful in solving the problem.
Since UVUV and VZVZ intersect at right angles within the circle W, we can apply the following property: If two chords are perpendicular, the sum of the measures of the arcs intercepted by the chords is 180 degrees. Let mUY=xm\angle UY = x. Then, mXZ=180xm\angle XZ = 180 - x.
Since UVYZUV \perp YZ, UY2+YX2=UX2UY^2 + YX^2 = UX^2 and UZ2+XZ2=4r2UZ^2 + XZ^2 = 4r^2.
Let UV=aUV = a, VX=bVX = b, YV=cYV = c, VZ=dVZ = d. Then, a+b=11a+b = 11 and c+d=17c+d = 17.
We need to find aa. Since we do not have sufficient information, we cannot solve this problem.
However, if we assume VV is the midpoint of UXUX, then UV=VX=11/2=5.5UV = VX = 11/2 = 5.5. This is an assumption, so we should state it. I will solve it under that assumption.
If VV is the midpoint of UX then UV=UX/2=11/2=5.5UV = UX/2 = 11/2 = 5.5
b) Find the measure of arc UYUY.
Since we know that the chords intersect at a right angle at point V, we know that mUVY=90m\angle UVY = 90^{\circ}.
mUYX=1/2mUXm\angle UYX = 1/2 * m\angle UX, so mUYX=1/2(80.6)=40.3m\angle UYX = 1/2 (80.6) = 40.3^{\circ}
Also mUY=1809040.3=49.7m \angle UY = 180^\circ - 90^\circ - 40.3^\circ = 49.7^\circ.
c) Find the length of VW.
We do not have enough information to calculate the length of VWVW. Since UVY=90\angle UVY = 90^{\circ}, UYUY and XZXZ are diameters. However we don't know the radius of the circle.

3. Final Answer

a) UV=5.5UV = 5.5 (assuming VV is the midpoint of UXUX)
b) mUY=49.7m\angle UY = 49.7^\circ
c) Cannot be determined without more information.

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