The problem asks us to find the next three terms in each of the given sequences.

AlgebraSequencesArithmetic SequencesGeometric SequencesNumber Patterns
2025/5/13

1. Problem Description

The problem asks us to find the next three terms in each of the given sequences.

2. Solution Steps

i) -8, 3, 14, 25, ...
The difference between consecutive terms are:
3 - (-8) = 11
14 - 3 = 11
25 - 14 = 11
Since the difference between consecutive terms is constant, this is an arithmetic sequence with a common difference of
1

1. Therefore, the next three terms are:

25 + 11 = 36
36 + 11 = 47
47 + 11 = 58
So, the next three terms are 36, 47, and
5
8.
ii) 1, 2, 8, 16, ...
This sequence can be interpreted in several ways. One possible pattern is:
1 = 202^0
2 = 212^1
8 is approximately 232^3.
16 = 242^4
Let's consider the differences between the exponents:
1-0 = 1
3-1 = 2
4-3 = 1
These don't seem to follow a clear pattern.
Another possible pattern is:
Multiply each term by successive powers of 2:
1 * 2 = 2
2 * 4 = 8
8 * 2 = 16
This also doesn't follow a clear pattern.
Let's examine differences between consecutive terms:
2-1 = 1
8-2 = 6
16-8 = 8
These differences don't seem to follow a clear pattern either.
However, let's consider the differences of the differences:
6-1 = 5
8-6 = 2
Again, no clear pattern is seen.
Alternatively, consider the sequence:
1, 2, 8, 16
Let's look at ratios of consecutive terms.
r1=2/1=2r_1 = 2/1 = 2
r2=8/2=4r_2 = 8/2 = 4
r3=16/8=2r_3 = 16/8 = 2
There seems to be no discernable pattern here.
The most appropriate way to find the next three terms is to consider the sequence as a function f(n)f(n).
If we observe the terms carefully, we can rewrite the sequence as follows:
a1=1=11a_1 = 1 = 1^1
a2=2=21a_2 = 2 = 2^1
a3=8a_3 = 8 approximately 323^2
a4=16a_4 = 16 is 424^2
This sequence has no logical continuation. It appears that no reasonable solution can be found.
If we assume that the sequence is a typo, and instead is 1, 2, 4, 8, 16, ... which is 2n2^n,
Then the terms are 20,21,22,23,24,...2^0, 2^1, 2^2, 2^3, 2^4, ...
The next three terms are 25,26,272^5, 2^6, 2^7
Which gives 32, 64,
1
2
8.
iii) 10, 50, 250, 1250, ...
The ratio between consecutive terms are:
50/10 = 5
250/50 = 5
1250/250 = 5
Since the ratio between consecutive terms is constant, this is a geometric sequence with a common ratio of

5. Therefore, the next three terms are:

1250 * 5 = 6250
6250 * 5 = 31250
31250 * 5 = 156250
So, the next three terms are 6250, 31250, and
1
5
6
2
5
0.

3. Final Answer

i) 36, 47, 58
ii) Assuming the sequence is a typo and it is a geometric sequence of powers of 2, we obtain 32, 64,
1
2

8. iii) 6250, 31250, 156250

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