Segments $PR$ and $PS$ are tangent to the circle. The measure of $\angle RPS = 66^{\circ}$. We need to find the measure of $\angle RQS$.

GeometryGeometryCirclesTangentsQuadrilateralsAngles
2025/5/13

1. Problem Description

Segments PRPR and PSPS are tangent to the circle. The measure of RPS=66\angle RPS = 66^{\circ}. We need to find the measure of RQS\angle RQS.

2. Solution Steps

Since PRPR and PSPS are tangent to the circle at points RR and SS respectively, we know that QRP=90\angle QRP = 90^{\circ} and QSP=90\angle QSP = 90^{\circ}.
Consider quadrilateral QRPSQRPS. The sum of the interior angles of a quadrilateral is 360360^{\circ}. Therefore,
RQS+QRP+RPS+QSP=360 \angle RQS + \angle QRP + \angle RPS + \angle QSP = 360^{\circ}
RQS+90+66+90=360 \angle RQS + 90^{\circ} + 66^{\circ} + 90^{\circ} = 360^{\circ}
RQS+246=360 \angle RQS + 246^{\circ} = 360^{\circ}
RQS=360246 \angle RQS = 360^{\circ} - 246^{\circ}
RQS=114 \angle RQS = 114^{\circ}

3. Final Answer

The measure of RQS\angle RQS is 114114^{\circ}.

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