A bag contains 4 marbles: 2 red, 1 blue, and 1 green. Amy removes one marble at a time from the bag. We need to determine which of the given sequences of colors is a possible outcome.

Probability and StatisticsProbabilityCombinatoricsConditional ProbabilityPermutations
2025/5/14

1. Problem Description

A bag contains 4 marbles: 2 red, 1 blue, and 1 green. Amy removes one marble at a time from the bag. We need to determine which of the given sequences of colors is a possible outcome.

2. Solution Steps

We examine each option to see if the sequence of colors is possible given the initial distribution of marbles.
A) Red -> blue -> red -> blue
Initially, there are 2 red, 1 blue, and 1 green. After drawing a red marble, there is 1 red, 1 blue, and 1 green. After drawing a blue marble, there is 1 red and 1 green. After drawing a red marble, there is 1 green. After drawing a blue marble is impossible, since there are no blue marbles left. Therefore, this option is not possible.
B) Green -> blue -> red -> green
Initially, there are 2 red, 1 blue, and 1 green. After drawing a green marble, there are 2 red and 1 blue. After drawing a blue marble, there are 2 red. After drawing a red marble, there is 1 red. After drawing a green marble is impossible since there are no green marbles left. Therefore, this option is not possible.
C) Blue -> red -> red -> green
Initially, there are 2 red, 1 blue, and 1 green. After drawing a blue marble, there are 2 red and 1 green. After drawing a red marble, there is 1 red and 1 green. After drawing a red marble, there is 1 green. After drawing a green marble, there are no marbles left. This option is possible.
D) Red -> blue -> green -> blue
Initially, there are 2 red, 1 blue, and 1 green. After drawing a red marble, there is 1 red, 1 blue, and 1 green. After drawing a blue marble, there is 1 red and 1 green. After drawing a green marble, there is 1 red. After drawing a blue marble is impossible since there are no blue marbles left. Therefore, this option is not possible.

3. Final Answer

C) Blue -> red -> red -> green

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