Given two functions $f(x) = 3\sqrt{x}$ and $g(x) = x^4 + 2$, we want to find the composite function $(f \circ g)(x)$, which is equal to $f(g(x))$.

AlgebraFunction CompositionAlgebraic Functions
2025/3/21

1. Problem Description

Given two functions f(x)=3xf(x) = 3\sqrt{x} and g(x)=x4+2g(x) = x^4 + 2, we want to find the composite function (fg)(x)(f \circ g)(x), which is equal to f(g(x))f(g(x)).

2. Solution Steps

The composite function (fg)(x)(f \circ g)(x) is defined as f(g(x))f(g(x)).
First, substitute g(x)g(x) into f(x)f(x):
f(g(x))=f(x4+2)f(g(x)) = f(x^4 + 2).
Now, we replace xx in the expression for f(x)f(x) with x4+2x^4 + 2:
f(x)=3xf(x) = 3\sqrt{x}
f(x4+2)=3x4+2f(x^4+2) = 3\sqrt{x^4 + 2}.
Thus, (fg)(x)=3x4+2(f \circ g)(x) = 3\sqrt{x^4 + 2}.

3. Final Answer

The final answer is (C) 3x4+23\sqrt{x^4+2}

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