The problem asks us to find the expression for $(f-g)(x)$ given $f(x) = x^2 - 1$ and $g(x) = x^2 + x$.

AlgebraFunction OperationsPolynomialsAlgebraic Manipulation
2025/3/21

1. Problem Description

The problem asks us to find the expression for (fg)(x)(f-g)(x) given f(x)=x21f(x) = x^2 - 1 and g(x)=x2+xg(x) = x^2 + x.

2. Solution Steps

We need to find (fg)(x)(f-g)(x), which is defined as f(x)g(x)f(x) - g(x).
f(x)=x21f(x) = x^2 - 1
g(x)=x2+xg(x) = x^2 + x
(fg)(x)=f(x)g(x)=(x21)(x2+x)(f-g)(x) = f(x) - g(x) = (x^2 - 1) - (x^2 + x)
(fg)(x)=x21x2x(f-g)(x) = x^2 - 1 - x^2 - x
(fg)(x)=x2x2x1(f-g)(x) = x^2 - x^2 - x - 1
(fg)(x)=x1(f-g)(x) = -x - 1
(fg)(x)=1x(f-g)(x) = -1 - x

3. Final Answer

The final answer is (C) 1x-1 - x.

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