The problem asks us to find the gradient ($m$) and the y-intercept for each of the two given graphs (a and b).

AlgebraLinear EquationsGradientY-interceptCoordinate Geometry
2025/5/14

1. Problem Description

The problem asks us to find the gradient (mm) and the y-intercept for each of the two given graphs (a and b).

2. Solution Steps

Graph a:
We are given one point on the line, (3, 5). From the graph, we can see that the line passes through the origin (0, 0).
We can use these two points to find the gradient mm. The formula for gradient is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the points (0, 0) and (3, 5), we have:
m=5030=53m = \frac{5 - 0}{3 - 0} = \frac{5}{3}
The y-intercept is the point where the line crosses the y-axis. From the graph, we can see that the line crosses the y-axis at (0, 0). Therefore, the y-intercept is
0.
Graph b:
We are given two points on the line, (0, 4) and (1, 0).
We can use these two points to find the gradient mm. The formula for gradient is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the points (0, 4) and (1, 0), we have:
m=0410=41=4m = \frac{0 - 4}{1 - 0} = \frac{-4}{1} = -4
The y-intercept is the point where the line crosses the y-axis. From the graph, we can see that the line crosses the y-axis at (0, 4). Therefore, the y-intercept is
4.

3. Final Answer

For graph a:
Gradient, m=53m = \frac{5}{3}
y-intercept = 0
For graph b:
Gradient, m=4m = -4
y-intercept = 4

Related problems in "Algebra"

We are given a system of four linear equations with four variables $a$, $b$, $c$, and $d$: \begin{al...

Linear EquationsSystems of EquationsSolving Equations
2025/5/15

Given a cubic function $f(x) = ax^3 + bx^2 + cx + d$, we need to find the coefficients $a, b, c,$ an...

Cubic FunctionsDerivativesRelative ExtremaCurve SketchingRoots of Equations
2025/5/14

We are given a cubic function $f(x) = ax^3 + bx^2 + cx + d$. We need to find the values of the coeff...

CalculusCubic FunctionsDerivativesLocal Maxima and MinimaTangent LinesSystems of Equations
2025/5/14

The problem is to solve the equation $(1-a)^3 = \frac{1}{2}$ for $a$.

EquationsCube RootsSolving EquationsAlgebraic ManipulationRationalization
2025/5/14

The problem is to solve for $a$ in the equation $(1 - a^5) = \frac{1}{2}$.

EquationsExponentsRootsAlgebraic Manipulation
2025/5/14

The problem asks to find the x and y intercepts of the equation $2x + y + 4 = 0$ and then sketch the...

Linear EquationsInterceptsGraphing
2025/5/14

The problem has two parts. Part 1: Find the equation of the lines in the form $y = mx + c$ for the g...

Linear EquationsSlope-Intercept FormX-interceptY-interceptGraphing
2025/5/14

The problem asks us to find the gradient and y-intercept for each of the given linear equations. The...

Linear EquationsGradientY-interceptCoordinate Geometry
2025/5/14

The problem is to solve the following system of equations for $x$ and $y$: $x - y = 1$ $4 > x^2 - y^...

Systems of EquationsInequalitiesAlgebraic ManipulationDifference of Squares
2025/5/14

We are given two sets of equations and asked to solve them. Set 1: $x^2 - y^2 = 3$ $x - y = 1$ Set 2...

Systems of EquationsQuadratic EquationsComplex NumbersDifference of Squares
2025/5/14